Part 1 of 2 Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of - 39.67°C
and a boiling point of 387.32°C. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C = 5/9(F-32))
Express the range as an inequality and in interval notation.

The substance will not be in liquid state in range -273.15  

(absolute zero) to -47.42  

and the temperature above 364.76  

Explanation:

The Substance will be in solid state in at the temperature below its melting point and it will be is gaseous state at the temperature above its boiling point. So it will be liquid between melting and boiling point.

Step-by-step explanation:

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

d

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