The diagram shows FGCE is the image of ABCD under and isometry. Given BCG is a straight line, determine angle DCE A. 36°
B. 67°
C. 54°
D. 46°

D

Step-by-step explanation:

The sum of the interior angles of a quadrilateral = 360°

∠ BCD = 360° - (90 + 90 + 113)° = 360° - 293° = 67°

ABCD and FGCE are congruent figures , then

∠ GCE = ∠ BCD = 67°

BCG isa straight line , so

∠ BCD + ∠DCE + ∠ GCE = 180° , that is

67° + ∠ DCE + 67° = 180°

∠ DCE + 134° = 180° ( subtract 134° from both sides )

∠ DCE = 46° → D

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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