Given square JKLM and t(-6,4) t (1,5) (JKLM)RSTU, what is the area of RSTU? Please help brainliest for correct answer.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24