Solve for a when b = 4 and c = 5. 3(c + 6) – 4b = 2b – 16 + 5(a + 1)

A=4
supstitute your b’s and c’a with its number. follow PEMDAS and do the parathensis first, next multiply, and solve from their

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.