In a group of 50 students 38 play chess and 24 play scrabble. How many plays both chess and scrabble.

12

Solve:

to solve, first add both partial numbers together

38 + 24 = 62

then subtract the whole number

62 - 50 = 12

Step-by-step explanation:

the way this works is the overflow when adding the two numbers, is the amount of students that do both, they count in both groups meaning their counted twice, this means that if each student dropped a coin for what they played (1 for chess and/or 1 for scrabble) the 12 students who played both would drop two coins

not a professional explanation but i hope it makes sense ^^

d

step-by-step explanation:

i used the pitagoras theoreme