Suppose we wish to find an upper bound for R 2 0 cos x 2 dx. Explain why we cannot doing so using only a left Riemann sum or only a right Riemann sum on the interval [0, 2]. (b) How can we adapt the ideas in the sample solution to develop a method that will give an upper bound for R 2 0 cos x 2 dx

first one because it can't have a fraction in it

step-by-step explanation:

answer: 33 ( approx)

step-by-step explanation:

since, in the linear regression formula, the slope is the a in the equation y = b + ax ( by comparing it with the general equation of line y = mx + c )

where,

here given table is,

price ($), x   :           18         23       25       29       30       33

pairs sold, y :         16         13         10       8         6       2

so, ,   ,   ,

and   ,

thus, slop of the given line is,

⇒  

⇒   ≈ 33

take the logarithm of both sides (the base of the log doesn't matter):

apply the exponent property - this says that :

distribute the log terms on both sides:

group like terms together:

divide through both sides by the coefficient on :

you can do some additional rewriting here using the properties of the logarithm to simplify things if you like: