A man is 32 years old than his son. Ten years ago he was three times as old as his son was then. Find the present age of each?
Pls explain all the steps

Let's say the man's age is X, and the son's age is y (capital has no distinction because I'm dealing with autocorrect here)

x-32=y

x-10=3(y-10)=3y-30

X+20=3y

3x-96=3y

Thus, X+20=3x-96, and 2x=116, X=58

Now, 58–32=y, thus, y=26

yeet

step-by-step explanation:

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.