Question Write an equation of the line passing through the point A(0, 3) that is perpendicular to the line y = −1/2x−6

The equation would be y=2x+3 I am pretty sure

Step-by-step explanation:

This is because you take the slope which is 2 from the line y=-1/2x-6. To find the slope perpendicular to the line, you need to find the exact opposite of the slope: -1/2, and in this case, it would be 2.

(Ex: if it was -3/4, you would need to use a slope of 4/3 since it is the opposite)

Then you take that slope (2) and the point (0, 3) and put it into "y-y1=m(x-x1)"

y-y1=m(x-x1)

y-3=2(x-0)

-distribute the 2-

y-3=2x-0

-add 3 on both sides-

so equation would be y=2x+3

Not sure if this is all correct, but I hope it helps! :)

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x