I'm solving the equation x^3+9x^2+16x-6=0, so I made a Descarte's Table; which told me I'd have 1 positive root and either 2 or 0 negative roots. However, the roots come out to be -3-√11, -3+√11, and -3. So my question is: why are none of the answers positive real numbers? I thought since the table said I'd have 1 positive that at least one of the answers would be as such. Am I doing something wrong? What am I missing?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

27 +27 or 27times 2=54

the diffrence is 0

what are the