PLEASE HELP write the equation in slope-intercept form of the line that passes through (6,-11) and is perpendicular to the graph of y=-2/3x+12

I believe the equation would be: y=3/2x-20

Step-by-step explanation:

This is true because, first you would need to find the slope from the equation, which is -2/3. But, for perpendicular, you would need to make it the exact opposite (which is this case would leave you with a slope of 3/2)

Ex: if you had -3/4, the slope for one that is perpendicular would be 4/3 (exact opposite)

After finding the slope, you take the points (6,-11) and plug it into the equation "y-y1=m(x-x1)"

y-y1=m(x-x1)

y+11=3/2(x-6)

-distribute the 3/2-

y+11=3/2x-18/2

y+11=3/2x-9

-subtract 11 on both sides-

y=3/2x-20

Im not sure if all calculations are correct, but I hope this helps! :)

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4