Consider the three non convex polygons drawn below. If the measure of an interior angle is allowed to be greater than 180, does the formula for the sum of the interior angles still hold for these figures? (attached is a very rough drawing of the figures)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome

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step-by-step explanation:

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