Tell whether each equation has one, zero, or infinitely many solutions. Solve the equation if it has one solution.

3(y - 2) = 3y - 6 PL HELPPP

3(y - 2) = 3y - 6

3y - 6 = 3y - 6

3y - 3y = - 6 + 6

0 = 0

It has ∞ solutions.

0 = 0, so 'y' can be replaced with any value & we'll still get the LHS & RHS as 0. So, the equation has ∞ solutions.

Hope it helps ⚜

Infinitely Many Solutions

Step-by-step explanation:

3(y - 2) = 3y - 6

3y - 6 = 3y - 6      Distribute 3.

0 = 0                    Combine the like terms.

Since we get the end result of 0 = 0, which is a true mathematical statement (i.e. 0 is equal to 0), we can see that regardless of the value of x, the original equation is true. So we have infinitely many equations.

Or, we can see the 2 parts as equations for 2 separate graphs. In other words, assume that we have 2 lines: y = (3x - 2) and y = 3y - 6. Since they both have the same m value (slope) and b value (y-intercept), the 2 lines are actually overlapping. So we have infinitely many solutions because the 2 equations represent the same linear graph.

250

step-by-step explanation:

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.