Li and Jen went shopping. • Li bought 5 pairs of earrings and 1 necklace for a total of $56.
• Jen bought 1 pair of earrings and 2 necklaces for a total of $40.

Each pair of earrings cost e dollars and each necklace cost n dollars. Which system of equations can be used to find the cost, in dollars, of each pair of earrings and each necklace?
A.
5e + 2n = $56
e + n = $40

B.
5e + n = $56
e + 2n = $40

C.
e + 5n = $56
e + 2n = $40

D.
5e + n = $56
2e + n = $40

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.