Which choice is the correct graph of|x1 <5? A
A
-6
5
3
-2
- 1
0
1
2
3
4
5
B
-
-5
.4
-3
.1
0
1
2
3
4
5
6
C
-5
-4
-3
- 1
1
2
3
4
5
6
D +
-4
0
2
3
5
6.
E-
-6
-5
-4
-3
-2
- 1
0
1
2
3
4
6
6
F
-6
-6
-4
-3
-2
-1
0
1
2
3
4
6
6
A. Graph A
B. Graph B
C. Graph C
D. Graph D
E.
Graph E
OF
Graph F

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

75

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.