1. A full box of crayons contains 8 crayons. If each of the 26 students in a class needs to use
1 crayon at the same time in a class activity, how many full boxes of crayons will be used?
How many more crayons will be needed in addition to the ones in these full boxes?

look a the sides they are perpendicular

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.