A 15 kg ball is thrown into the air. It is going at 4m/s when thrown. How much potential energy will it have at the top?

P.E = mgh = 120N

Step-by-step explanation:

v² = u² - 2as

At the top, the velocity is = 0

0² = 4² - 2 x 10 x s

4² = 20s

s = 16/20

s = 0.8metres.

It rose only 0.8metres.

Therefore P.E = 15 x 10 x 0.8

:. P.E = 15 * 8

:. P.E = 120N

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

answer: x=60