Write a cosine function for the graph. 4
O
12 &
2
0
-2
4-
a.
.
e
y = -3 cos
c.
c
os
y = 3 cos
=
b. y = 3 cos 30
d. y = -3 cos 30

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

addition

step-by-step explanation: