Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was three eighths the size of the brand name. If the generic television set is 12 inches by 24 inches, what are the dimensions of the brand name television?

Option (C) is correct, the dimensions of the brand name television = 32 inches by 64 inches.

Step-by-step explanation:

Given :  The generic version was based on the brand name and was three eighths the size of the brand name and both are similar.

The dimensions of the generic television set = 12 inches by 24 inches

Let the dimensions of brand name be x by y such that

three eighth of x=12 inches

and three eighth of y=24 inches

Therefore, the dimensions of the brand name television = 32 inches by 64 inches.

Hence option (C) is correct.

26?

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)