Lacey drops a stone off a cliff. The speed of the stone changes as it falls. The speed is modelled using the formula v= 10t + 15, where v represents the speed of the stone, in metres per second, and t represents the time, in seconds. a) What is the speed of the stone one second after it is dropped?

b) At what time is the speed of the stone 45 m/s?

((see pic of textbook question if wanted))

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

the correct answer would be:

220 centimeters

to get this you can use the pythagorean theorem

hope this

step-by-step explanation: