PLEASE HELP Write the system of equations for the following scenario: The sum of twice the square of the first number plus the second number is 9.
The difference between twice the first number and the second number is 15.
Linear Equation:
Quadratic Equation:

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation:

its a lot blury

10 times 13 = 130

10 times 13 = 130

130 + 130 = 260

if this you out can you make this answer the brainliest?

no it isn’t   i believe it is

step-by-step explanation: