Write an equation for the line parallel to the line – 25x + 5y = -9 through the point (0,0). help pls!

Step-by-step explanation:

Rewrite the equation is standard format:  y = mx + b, where m is the slope and b is the y-intercept (the value of y when x=0).  \

– 25x + 5y = -9

5y = 25x - 9

y = 5x - (9/5)

This line has a slope of 5.  A parallel line will have the same slope as the reference line.  This means:

y = 5x + b

Any line with a slope of 5 will be parallel, regardless of the value of b.  We need b, however, since we also want this line to cross point (0,0).  We can use this point in the equation and solve for b:

y = 5x + b

0 = 0x + b

b = 0

Our line becomes y = 5x + 0, or

y = 5x  

[Note that we could also say b=0 just by looking at the given point.  The y-intercept, b, is the value of y when x=0.  The point we were given tells us y = 0 at x = 0.

sorry, i don't know i just need points, i'm new here. chao