Which equation represents the line that passes through the points (0, 3) and (2,6) A y = -3/2x + 3

B y = 2/3x + 3

C y = 3/2x + 3

D y = 3/2x

C) y=3/2x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-3)/(2-0)

m=3/2

y-y1=m(x-x1)

y-3=3/2(x-0)

y=3/2(x)+3

y=3/2x+3

C) y=3/2x+3

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-3)/(2-0)

m=3/2

y-y1=m(x-x1)

y-3=3/2(x-0)

y=3/2(x)+3

y=3/2x+3

it should be a and d. lmk if i'm wrong xd

the answer to the expression is 83