What is the hypotenuse of a right triangle with a and b related by the statement a=b-5.

c = 5b ±sqrt(-10(b+a)+2)

Step-by-step explanation:

By using the Pythagoras theorem,

c² = a² + b²

a = b-5

b = a+5

c² = (b-5)² + (a+5)²

c² = b²-10b+25 + a²+10a+25

c² = b²-10b-10a+50

c² = b²-10(b+a)+50

c = 5b ±sqrt(-10(b+a)+2)

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