How does (x^3)^3 = x^6 ?

It does not, unless or

If you remember how to raise a power to a given power you remember to multiply the exponents (or, if you don't, apply the definition of

At this point you're being asked if and the only two numbers for which this is true are 0 and 1 (side note: if the left hand side was an even function also was a possible candidate, but alas 9 is odd).

answer: i'm great at algebra

~coco

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?