Insert two rational number between 1.3 bar and 1.4 bar

General method:

Given numbers are 1.3 bar and 1.4 bar

Two rational numbers between them

= 1.3222... and 1.43333...

Mean Method:

Let X = 1.333... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.333...×10

⇛10X = 13.333... → → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 13.333...

X = 1.333...

(-)

9X = 12.000...

⇛9X = 12

⇛X = 12/9

⇛X = 4/3

and

Let X = 1.444... → → →eqn(i)

since the periodicity is 1 then multiply eqn(i) with 10

⇛10×X = 1.444...×10

⇛10X = 14.444...→ → →eqn(ii)

Subtract eqn(ii)-eqn(i)

10X = 14.444...

X = 1.444...

(-)

9X = 13.000...

⇛9X = 13

⇛X = 13/9

Now we have 12/9 and 13/9

The rational number between them by mean method (a+b)/2

⇛{(12/9)+(13/9)}/2

⇛(25/9)/2

⇛25/18

and Second rational number

⇛{(12/9)+(25/18)}/2

⇛{(24+25)/18}/2

⇛(49/18)/2

⇛49/36

Answer: The two rational numbers between them are 25/18 and 49/36.

also read similar questions: INSERT TWO RATIONAL NUMBERS BETWEEN 2 AND 3. How to find them?

the answer is 0.071

good luck! : d

answer: i believe it’s 245.04

step-by-step explanation: