Find the slope and the y-intercept of the graph of the linear equation. y=-7x + 2 A A) slope: - *- x-intercept: 2 : Đ) slope: 5 i -intercept: - C) slope: -7; z-intercept 2 Di slope: 2: y-intercept: -7

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation:

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

126 maybe. sorry