A summer camp cookout is planned for the campers and their families. There is room for 450 people. Each adult costs $7, and each camper costs $4. There is a maximum budget of $1,150. Write the system of inequalities to represent this real-world scenario, where x is the number of adults and y is the number of campers. X y ≤ 1,150 7x 4y ≤ 450 x y ≤ 450 7x 4y ≤ 1,150 x y ≤ 1,150 4x 7y ≤ 450 x y ≤ 450 4x 7y ≤ 1,150.

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0