Write an equation in slope-intercept form of the line with 3 and that passes through the point
(3,3).

Hi there!

We are given the slope of the line and a point that the line passes through.

We can write its equation in point-slope form first:

y-y1=m(x-x1)

y-3=3(x-3)

y-3=3x-9

y=3x-9+3

y=3x-6

Therefore, that's the answer. Hope it helps.

Let me know if you have any questions.

~GracefulGirlie

Good luck on your assignment.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°