Chelseas school is selling tickets to o a play. On the first day of tickets sales the school sold 4 senior citizen tickets and 8 child tickets for a total of $68. The school took in $42 on the second day by selling the 2 seniors citizen tickets a 6 child tickets. What is the price each of one senior citizen ticket and one child ticket?

The answer is 14 for each child and 8 each senior.

Step-by-step explanation:

0 + 1c = $14 for one child ticket

:

Find s using the equation 3s + 1c = 38, replace c with 14

3s + 14 = 38

3s = 38 - 14

3s = 24

s = 24/3

s = $8 for each senior

:

:

You can check these solutions using the 2n equation

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

is the anwser b. (-13)?