Find the equation of the line parallel to y-8= 2/3x that passes through the point (-9-9)

y = (2x/3) - 3

Step-by-step explanation:

parallel means same slop

y=2x/3 + b

-9 = -6 + b

b = -3

therefore y = (2x/3) - 3

y = 2/3x - 3

Step-by-step explanation:

let's put equation into slope-intercept form first, which is y=mx+b where 'm' is the slope and 'b' is the y-intercept

y-8 = 2/3x

y = 2/3x+8

parallel lines have equal slopes, so we know our equation must have a slope of 2/3

now use (-9,-9) to find 'b':

-9 = 2/3(-9) + b

-9 = -6 + b

-3 = b

put it together:

y = 2/3x - 3

i dont know sorry

step-by-step explanation:

the square root of what number? if you add that, then someone will probably answer the question.