Consider a binomial distribution with n = 10 trials and the probability of success on a single trial p = 0.85. (a) Is the distribution skewed left, skewed right, or symmetric?

(b) Compute the expected number of successes in 10 trials.

(c) Given the high probability of success p on a single trial, would you expect P(r ≤ 3) to be very high or very low? Explain.
1) Very low. The expected number of successes in 10 trials is more than 3, and p is so high that it would be common to have so few successes in 10 trials.
2) Very high. The expected number of successes in 10 trials is more than 3, and p is so high that it would be unusual to have so few successes in 10 trials.
3) Very low. The expected number of successes in 10 trials is more than 3, and p is so high that it would be unusual to have so few successes in 10 trials.
4) Very high. The expected number of successes in 10 trials is more than 3, and p is so high that it would be common to have so few successes in 10 trials.

(d) Given the high probability of success p on a single trial, would you expect
P(r ≥ 8) to be very high or very low? Explain.

1) Very low. The expected number of successes in 10 trials is more than 8, and p is so high that it would be unusual to have 8 or more successes in 10 trials.
2) Very low. The expected number of successes in 10 trials is more than 8, and p is so high that it would be common to have 8 or more successes in 10 trials.
3) Very high. The expected number of successes in 10 trials is more than 8, and p is so high that it would be common to have 8 or more successes in 10 trials.
4) Very high. The expected number of successes in 10 trials is more than 8, and p is so high that it would be unusual to have 8 or more successes in 10 trials.