a number card numbered from 1 to 30 is drawn randomly. what is the probability of getting the card having the number which is the multiple of 5 or 6

Explanation:

A = multiples of 5 between 1 and 30

A = {5,10,15,20,25,30}

B = multiples of 6 between 1 and 30

B = {6,12,18,24,30}

There are 6 items in set A and 5 items in set B. This gives 6+5 = 11 items overall; however, notice that "30" shows up twice. So we have to subtract off 1 to account for this. This means there are 11-1 = 10 unique values that are either a multiple of 5, a multiple of 6, or a multiple of both. This is out of 30 numbers in the set {1, 2, 3, ... , 29, 30}

The probability we want is 10/30 = 1/3

the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

b i think

step-by-step explanation:

not really sure