The total cost of trousers and three coats is 52 usd and the total cost 4 trousers and 4 coats is 72 usd what is the total cost of 6 trousers and coats?

Step-by-step explanation:

Let,

Cost of one trouser = $x

Cost of one coat = $y

In case 1

x + 3y = 52 (1)

In case 2

4x + 4y = 72

x + y = 18 (2)

On subtracting

x + 3y - (x + y) = 52 - 18

x + 3y - x - y = 52 - 18

2y = 34

y = 34/2

y = $17

From 2

x + y = 18

x + 17 = 18

x = 18 - 17

x = $1

Now,

Cost of 6 trouser and 6 coats

6x + 6y

6(x + y)

6(1 + 17)

6(18)

$108

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step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0