How would you graph the solution set of x - 2 > 5? Open circle on 7 and shaded to the right.
Closed circle on 7 and shaded to the right.
Open circle on 7 and shaded to the left.
Closed circle on 7 and shaded to the left.

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

i believe so, according to my "strange" way of figuring out weird math problems like this.