WILL GIVE BRAINLIEST!! Which is one solution, no solution, and infinite solutions?

3(4x-2) = 12x - 6
3(4x-2)= -12x - 6
-3(4x-2) = -12x - 2

Step-by-step explanation:

3(4x - 2) = 12x - 6

12x - 6 = 12x - 6

that is always true, no matter what value we pick for x.

so, this has infinite many solutions.

3(4x - 2) = -12x - 6

12x - 6 = -12x - 6

24x = 0

x = 0

this has one solution.

-3(4x - 2) = -12x - 2

-12x - 6 = -12x - 2

-6 = -2

this is never true, no matter what value we pick for x.

so, this has no solution at all.

see below

Step-by-step explanation:

Hi!!

Here's how I found it:

First, I simplified all my equations.

1.12x-6=12x-6

2.12x-6=-12x-6

3.-12x+6=-12x-2

#1 has infinite solutions, given that the equations are identical to eachother. Any value of x will sufice.

#2 can be simplifed with algebra.

Cancel out the -6, since it is on both sides.

we are left with 12x=-12x, which can be solved with the value of 0. This has one solution.

#3 can also be simplifed using algebra.

Cancel out the -12x, since both sides have that.

you are left with:

6=-2

this will never have a solution, therefor, it is no solution.

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

this doesn't make sense lol