Make x the subject of the formula,
y (x-4) squared +6

Is "y (x-4) squared +6":     y = (x-4)^2 + 6?

If so,

x = y^(1/2) - 6^(1/2) + 4

Step-by-step explanation:

y^(1/2)= (x-4) + 6^(1/2)

(x-4) = y^(1/2) - 6^(1/2)

x = y^(1/2) - 6^(1/2) + 4

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p

1,8,15,22,29,36,43,50

step-by-step explanation: