To solve for the hypotenuse of a right triangle, what information do you need?

To find the hypotenuse of any right triangle, you need to square and add the other two sides. We call those two sides LEGS.

(legs)^2 + (leg)^2 = (hypotenuse)^2

In your textbook, you will see it this way:

a^2 + b^2 = c^2, where a = b = legs.

You can use Sin to solve that problem in it you should have Angle=theeta and perpendicular.

Step-by-step explanation:

First you should have Perpendicula and Then Angle Put That info in Sinɵ = perpendicular/base. Solve it and get your Answer

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1