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Mathematics, 25.12.2021 18:30 he0gaubong

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It is the expression
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$for \: x \: such \: that \: 0 < x < \frac{\pi}{2}$
$\frac{ \sqrt{1 - {cos}^{2}x } }{sin \: x} \:- \frac{ \sqrt{1 - {sin}^{2}x } }{cos \: x} \\ \\ is \: equivalent \: to:$
$f.0 \\ g.1 \\ h.2 \\j. - tan \: x \\ k. \: sin \: 2x$

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