Two planes leave an airport flying at the same rate. if the first plan files 1.5 hours longer than the second plan and travels 2700 miles while the second plane travels only 2025 miles, for how long was each plan flying?

Plane 1 was in the air for 6 hours, Plane 2 took 4.5 hours.

Step-by-step explanation:

subtract Plane 2's miles by Plane 1's: 675. Thus, it took Plane 1 1.5 hours to travel 675 miles. Divide the miles by hours and you get 450 MPH. Then, divide each mile figure by the MPH figure to get the time that each plane was in the air: Plane 1 was in the air for 6 hours, Plane 2 took 4.5 hours.

I hope that I was fast enough, and that this is correct.

yo answer should be 6 if im not mistaken

step-by-step explanation:

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4