What is the area of the polygon? 96 cm2 256 cm2 112 cm2 64 cm2

The figure is composed by 2 Isosceles Triangles (Two equal sides) and one Rectangle in the middle.

Triangle Area = 1/2 × base× height

Rectangle Area = length×width

- Triangles:

Base: 16cm

Height: 6cm

- Rectangle:

Length: 16cm

Width: 10cm

Triangle Area (At):

- At = 16 x 6/2

- At = 96/2

- At = 48 cm^2

Rectangle Area (Ar):

- Ar = 16 x 10

- Ar = 160 cm^2

Total Area = 2 x (Triangle Area) + Rectangle Area

Total Area = 2 x 48 + 160

Total Area = 96 + 160

Total Area = 256cm^2

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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step-by-step explanation: