Find the equation of a line that passes through the point (0,1) and has a gradient of -3.
Leave your answer in the form y = mx + c

An intercept of 4 on the y-axis - in point (0,4)

\dfrac{x-x_a}{x_b-x_a}=\dfrac{y-y_a}{y_b-y_a} \\ \dfrac{x-3}{0-3}=\dfrac{y-0}{4-0}\\ \dfrac{x-3}{-3}=\dfrac{y}{4}\\ y=-\dfrac{4}{3}x+4

x

b

−x

a

x−x

a

=

y

b

−y

a

y−y

a

0−3

x−3

=

4−0

y−0

−3

x−3

=

4

y

y=−

3

4

x+4. cheera

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.