Which of the following is equivalent to (2a^2-6ab+4b^2)-(-a^2+2ab-2b^2)

(2a^2-6ab+4b^2)-(-a^2+2ab-2b^2)

=2a^2-6ab+4b^2+a^2-2ab+2b^2

=2a^2+a^2-6ab-2ab+4b^2+2b^2

=3a^2-8ab+6b^2

bru

step-by-step explanation:

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions