What does f mean in f(x)=3/2x+2?

Also do the two points 0,2 and 2,5 work with the equation?

(0, 2) and (2, 5) are solutions to the function.

Step-by-step explanation:

Given the following linear function:

"f(x)" is a function notation.  

"f" represents the function name. In function notations, you can use any letter to represent a function name. However, "f" is commonly used to express function notations.

"x" is your input variable. This is the x-values that you substitute into the function to get an output, or y-value.

f(x) is your output value.

We are also given the following points:  (0, 2) and (2, 5).

In order to determine whether these points work with the given function, simply substitute their values into the function.

 ⇒ The function notation, "f(0)" simply means the function of zero, which corresponds to the input value of zero (0).

Next, substitute the value of y = 2 into the function as an output value:

2 = 0 + 2

2 = 2 (True statement).  This means that the point, (0, 2), is a solution to the given function. The point (0, 2) represent the given function's y-intercept, which is the point on the graph where it crosses the y-axis.  The y-coordinate of 2 is the value of b in the slope-intercept form, y = mx + b.

We will do the same process for (2, 5):

Substitute the value of y = 5 into the function as an output value:

5 = 3 + 2

5 = 5 (True statement).  This means that the point, (2, 5), is also a solution to the given function.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2