A quadrilateral has vertices A{11, -7), B(9,-4), C11,-1), and D(13,-4). Quadrilateral ABCD is a if the vertex C( 11, -1 ) we’re shifted to the point C ( 11, 1 ), quadrilateral ABCD would be a

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Quadrilateral ABCD is a parallelogram

if the vertex C( 11, -1 ) we’re shifted to the point C ( 11, 1 ), quadrilateral ABCD would be a kite

Step-by-step explanation:

without solving, im guessing that quad ABCD is a paralellogram (//gram)

lets test this theory

see if the slope of AB and CD, and BC and AD is the same

slope AB and CD

AB:

-7--4/11-9

=-3/2

CD:

-1--4/11-13

=3/-2

=-3/2

slope is the same

slope BC and AD

BC:

-4--1/9-11

=-3/-2

=3/2

AD:

-7--4/11-13

=-3/-2

=3/2

slope is same

because 2 pairs // sides ---> //gram

if the vertex C( 11, -1 ) we’re shifted to the point C ( 11, 1 ), quadrilateral ABCD would be a kite

hope this helps!

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yes yes yes yes yes yes yes yes yes

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)