g A bag contains 7 nickels, 2 dimes, and 8 quarters. If you draw 3 coins at random from the bag, without replacement, what is the probability that you will get a nickel (N), a quarter (Q), and a nickel (N), in that order

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

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blogan.20174

i saw this question before, dont know the asnwer srry

step-by-step explanation: