A city is building a fence around a rectangular playground if the perimeter of the playground is 104 feet and the length of one side of the fence is 32 feet what is the width of the play ground

20 ft

Step-by-step explanation:

We know that

Perimeter of rectangle = 2(l + w)

Let the width be w

=> 104 = 2(32 + w)

=> 104/2 = 32 + w

=> 52 = 32 + w

=> 52 - 32 = w

=> 20 = w

Hence z

Width of playground is 20 ft

Basic fact:

perimeter is (one side x by 2) + (the other side x by 2)

Step-by-step explanation:

To find the other side we have been already given the total which is 104

We have also been given one side which is 32

we need to times 32 by 2 which is 64

subtract 64 from 104 which is 40

divide 40 by 2 which is 20