The absolute maximum value of f(x)= x^3– 3x^2 +12 on the closed interval [-2, 4] occurs at x = A.4
B.2
C.1
D.0
E.-2

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

answer: entity is prob the answer

step-by-step explanation: