One-half the sum of two consecutive odd integers is −12. Find the smallest integer.

Step-by-step explanation:

Let the larger integer = 2x + 1

Let the second integer = 2x - 1

1/2 (2x + 1 + 2x - 1) = - 12               Combine the left

1/2(4x) = - 12                                  Combine 1/2 (4x)

2x = - 12                                         Divide by 2

2x/2 = - 12/2

x = - 6

2x + 1 = 2*-6 + 1 = -11

2x - 1 = 2*-6 - 1  = - 13

Check

-11 + - 13  = - 24

1/2(-24) = -12                               which checks.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier