PLEASE I NEED A DETAILED EXPLANATION
I WILL GIVE BRAINLIEST

Force on ladder 1 (left): 30.4 N

Force on ladder 2 (right): 60.8 N

Step-by-step explanation:

Given the left ladder is 1 then right ladder is 2

So distance from ladder 1 to center of mass d1 is 1.00 m

then distance from ladder 2 to center of mass d2 is 0.5 m (1.50 - 1.00)

The torque in ladder 1 is t1 while torque in ladder 2 is t2

so t1 = t2

since t = Fd

t1 = t2

F1d1 = F2d2

F1 = 0.5F2

since all equilibrium is 0, the sum of all forces

Force on ladder = F1 + F2

91.2 = F1 + F2

since F1 = 0.5F2

91.2 = 0.5F2 + F2

F2 = 91.2/1.5 = 60.8

F1 = 0.5F2 = 0.5(60.8) = 30.4

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐