Answer fast with explanation for brainliest!! A diner offers a lunch special. Customers
have a choice of a sandwich (chicken, turkey
a
veggie), a side (an apple, chips), and a drink
(water, juice). What is the probability of a
customer randomly choosing a combination
package that has chips and juice?

Step-by-step explanation:

First, We do the multiplication law. which states that if

R can occur multiple ways, n, then the total numbers of ways is just

In this case, we have 3 things to consider so we just do

number of sandwiches which is 3: Number of sides to choose from which is 2: And number of drinks: 2 so we do

So there is 12 possible combinations. Now let see which ones contine chips and juice.

We can make a tree diagram, and see that we can do

Chicken,Chips, and Juice

Turkey, Chicken,Juice

Or Veggie,Chicken, and Juice so there is 3 combinations that includes that.

So out of 12 combinations, there is 3 that favor our scenario so we say

Probability is 3/12=1/4=25%

the final amount you will pay is $68.04.

the tip is determined by the pre-tax amount, so we calculate the tip based on the original bill, not after we've added sales tax.

to find the tip:

we can divide 54.00 by 100 to get 1% of 54. then we multiply that by 18.

54 / 100 = .54

.54 x 18 = 9.72

tip = 9.72$

to find the tax:

we can divide 54.00 by 100 to get 1% of 54. then we can multiply that by 8 to get 8%.

54 / 100 = .54

.54 x 8 = 4.32

tax= 4.32

now we can add the tip and tax to the bill to get our total.

54 + 9.72 + 4.32 = 68.04

total: $68.04

step-by-step explanation: